IUPAC Nomenclacture of Inorganic Compounds and Concept of Oxidation Number
Oxidation number is the charge on the valency of an element, i.e.
Oxidation state = Valency + Charge
The valency of metal carries a positive charge, e.g. Na+ while the valency of non-metal carries the negative charge, e.g. Cl–
The total oxidation state of any compound is zero. This is gotten by adding the oxidation number of all the elements in a compound. For example, zinc chloride ZnCl2
Oxidation number of Zn = +2 and Cl = -1
Oxidation number of Zn + 2 x Oxidation number of Cl
= +2 + (2 x -1)
= +2 – 2 = 0
Some elements exhibit variable oxidation state, e.g. copper, lead, nitrogen and iron.
Example 1: Find the oxidation state of nitrogen in the following: (i) N2O (ii) NO (iii) NH3 (iv) NO2 (v) NO3
Solution:
(1) The sum of oxidation state of N2O = 0
The oxidation number of oxygen = -2
N2O = 0
2 x N + (-2) = 0
2N – 2 = 0
2N = +2
N = +2/2
N = +1
The oxidation state of nitrogen in N2O is +1 and the name of the compound is dinitrogen (I) oxide.
(2) Oxidation state of nitrogen in NO
NO = 0
N + (-2) = 0
N = 0 + 2
N = +2
The oxidation state of nitrogen in NO is +2. Hence, the name is nitrogen (II) oxide.
(3) Oxidation state of nitrogen in NH3
N + 3H = 0
N + 3 x +1 = 0
N = 0 – 3
N = -3
The oxidation state of nitrogen in NH3 is -3. Hence, the name is ammonia.
(4) Oxidation state of Nitrogen in NO2
N + 2O = 0
N + 2 x -2 = 0
N = 0 + 4
N = +4
The oxidation state of nitrogen in NO2 is +4. Hence, the name is nitrogen (IV) oxide
(5) In a radical or an ion, the sum of the oxidation state is equal to its charge.
Oxidation state of nitrogen in NO3–
N + 3O = -1
N – 2 x 3 = -1
N – 6 = -1
N = -1 + 6
N = +5
The oxidation state of nitrogen in NO3- is +5. Hence, the name is Trioxonitrate (V).
Example 2: Find the oxidation number of the manganese in potassium tetraoxomanganate (VII) KMnO4
Solution: Oxidation state of potassium is +1
Oxidation state of oxygen is -2
kMnO4 = 0
K + Mn + 4O = 0
+1 + Mn + 4 x -2 = 0
+1 + Mn – 8 = 0
Mn – 7 = 0
Mn = 0 + 7
Mn = +7
The oxidation number of the manganese in potassium tetraoxomanganate (VII) is +7.
Example 3: Find the oxidation number of the chromium in potassium heptaoxodichromate (VI) K2Cr2O7.
Solution: Oxidation number of K = +1 and Oxidation number of oxygen = -2
K2Cr2O7 = 0
+1 x 2 + Cr x 2 + (-2 x 7) = 0
+2 + 2Cr – 14 = 0
2Cr – 12 = 0
2Cr = 0 + 12
Cr = +12/2
Cr = +6
The oxidation number of chromium in potassium heptaoxodichromate (VI) is +6
The IUPAC names of some salts:
KClO4 = Potassium tetraoxochlorate (VII)
Ca(NO3)2 = Calcium trioxonitrate (V)
CuSO4 = Copper (II) tetraoxosulphate (VI)
Na2CO3 = Sodium trioxocarbonate (IV)
FeSO4 = Iron (II) tetraoxosulphate (VI)
Fe(SO4)3 = Iron (III) tetraoxosulphate (VI)
Example: Interprete the compounds represented by the formulae (i) Ca(NO3)2 (ii) Fe2(SO4)3 (iii) KNO3
Solution:
- Ca(NO3)2 represents 1 molecule of calcium trioxonitrate (V), containing:
- 1 atom of Calcium (Ca)
- 2 atoms of Nitrogen (N)
- 6 atoms of Oxygen (O)
- Fe2(SO4)3 represents 1 molecule of iron (III) tetraoxosulphate (VI), containing:
- 2 atoms of Iron (Fe)
- 3 atoms of Sulphur (S)
- 12 atoms of Oxygen (O)
- KNO3 represents 1 molecules of potassium trioxonitrate (V), containing:
- 1 atom of Potassium (K)
- 1 atom of Nitrogen (N)
- 3 atoms of Oxygen (O)
EXERCISES
Lets see how much you’ve learnt, attach the following answers to the comment below
- 3NH3 is (a) three moles of ammonium (b) three moles of ammonia (c) six moles of ammonia (d) six moles of ammonium
- What is the oxidation number of sulphur in H2SO4? (a) +2 (b) +4 (c) +6 (d) +7
- Find the oxidation number of Manganese atom in KMnO4. (a) +7 (b) -7 (c) +6 (d) -6
- _________ is the charge on the valency of an element. (a) reduction number (b) mole number (c) oxidation number (d) isotopy
- What is the IUPAC name of this compound Fe2O3? (a) iron (II) oxide (b) iron monoxide (c) iron (IV) oxide (d) iron (III) oxide
4 thoughts on “Classwork Series and Exercises {Chemistry- SS1}: IUPAC Nomenclacture of Inorganic Compounds and Concept of Oxidation Number”
No.1 C No.2 C No.3A No.4C
(1)d(2)c(3)b(4)c(5)d
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