There are 3 animals in consideration. A rabbit, a dog and something in form of a kitten.
On d first scale was d kitten like animal and a rabbit and dey jointly weigh 10kg. Figuring out d weight of each animal is impossible at dis point so we’ll look at d next set of animals which happens to be a dog and d same rabbit with a joint weight of 20kg. Won’t want to do some simultaneous equations here but will hit d nail on d head. D addition of both weights is equivalent to 30kg ie 10kg 20kg = 30kg. With our attention fixed on d third weight(d dog and kitten) which equals 24. Hence, 30kg-24kg = 6kg(subtracting d third weight from d addition of d first two weights). Since we av only a don and kitten on d third scale, it sure means dey share 24kg between demselves. And d 6kg goes to d rabbit and since we av d rabbit on two scales we can give d rabbit 3kg(x2 = 6kg) since d rabbit weighs 3kg, on d first scale 10kg – 3kg =7kg and dats for d kitten. For d dog. 20 kg – 3kg=17kg. Wif dat, d 3rd weight is sorted out. For d fourth, just add both 3 7 17(kg) and u’ll get 27kg.
There are 3 animals in consideration. A rabbit, a dog and something in form of a kitten.On d first scale was d kitten like animal and arabbit and dey jointly weigh10kg.Figuring out d weight ofeachanimal is impossible at dis point so we’ll look at d next set of animals ”dog kitten” with a joint weight of 20kg. D addition of both weights is equivalent to 30kg ie 10kg 20kg = 30kg. With our attention fixed on d third weight(d dog and kitten) which equals 24. Hence, 30kg-24kg = 6kg(subtracting d third weight from d addition of d first two weights). Since we av only a don and kitten on d third scale, it sure means dey share 24kg between demselves. And d 6kg goes to d rabbit and since we av d rabbit on two scales we can give d rabbit 3kg(x2 = 6kg) since d rabbit weighs 3kg, on d first scale 10kg – 3kg =7kg and dats for d kitten. For d dog. 20 kg – 3kg=17kg. Wif dat, d 3rd weight is sorted out. For d fourth, just add both 3 7 17(kg) and u’ll get 27kg.
There are 3 animals in consideration. A rabbit, a dog and something in form of a kitten.On d first scale was d kitten like animal and arabbit and dey jointly weigh10kg.Figuring out d weight ofeachanimal is impossible at dis point so we’ll look at d next set of animals ”dog+kitten” with a joint weight of 20kg. D addition of both weights is equivalent to 30kg ie 10kg + 20kg = 30kg. With our attention fixed on d third weight(d dog and kitten) which equals 24. Hence, 30kg-24kg = 6kg(subtracting d third weight from d addition of d first two weights). Since we av only a don and kitten on d third scale, it sure means dey share 24kg between demselves. And d 6kg goes to d rabbit and since we av d rabbit on two scales we can give d rabbit 3kg(x2 = 6kg) since d rabbit weighs 3kg, on d first scale 10kg – 3kg =7kg and dats for d kitten. For d dog. 20 kg – 3kg=17kg. Wif dat, d 3rd weight is sorted out. For d fourth, just add both 3 + 7 + 17(kg) and u’ll get 27kg.
Final Answer 27KG. Kindly see my working as shown below:
Let R represent the Rabbit and S represent the Sheep and D represent the Dog
R= Rabbit, S=Sheep and D=Dog
From the Scale:
Rabbit + Sheep Only =10 kg
R + S = 10——– Equation (1)
Rabbit + Dog= 20 kg
R + D = 20 ——– Equation (2)
And
Dog + Sheep = 24 Kg
D + S = 24 ——– Equation (3)
From Equation (1), make R the subject of Formula, R being the Common Entity;
R + S = 10
R = (10 – S)
Substituting for R in Equation (2), we have
R + D = 20, so,
(10-S) + D = 20
Which becomes
D – S = 20-10
D – S = 10
D = (10 + S) ——– Equation (4)
Now Substituting D from Equtn 4 into Equatn 3
We have ,
D + s = 24 ——– Equation 3
(10 + S) +S =24
2S =24-10
S=14/2
S=7
From the Making of R the initial subject of formula
R = (10 – S)
R = ( 10 – 7)
R = 3
Now that we know the Weight of the Rabbit and that of the Sheep, by usinf equation 4 we have,
D = (10 + S)
D = (10 + 7)
D = 17
By Adding all the (R + S + D ) together we have the Weight of all the animals
Weight of all Animals = R + S + D = (3 + 7 + 17) = 27 Kg
Final Answer: 27 KG
27 thoughts on “A little brain teaser: What’s your answer?”
27
Ishola
It’s 22
I go with IBK. 27
30
27
You guys should tell us how you’re arriving at your answers
Ya, it’s 27
25
25
26kg
30
The answer is 27
27
27
27
There are 3 animals in consideration. A rabbit, a dog and something in form of a kitten.
On d first scale was d kitten like animal and a rabbit and dey jointly weigh 10kg. Figuring out d weight of each animal is impossible at dis point so we’ll look at d next set of animals which happens to be a dog and d same rabbit with a joint weight of 20kg. Won’t want to do some simultaneous equations here but will hit d nail on d head. D addition of both weights is equivalent to 30kg ie 10kg 20kg = 30kg. With our attention fixed on d third weight(d dog and kitten) which equals 24. Hence, 30kg-24kg = 6kg(subtracting d third weight from d addition of d first two weights). Since we av only a don and kitten on d third scale, it sure means dey share 24kg between demselves. And d 6kg goes to d rabbit and since we av d rabbit on two scales we can give d rabbit 3kg(x2 = 6kg) since d rabbit weighs 3kg, on d first scale 10kg – 3kg =7kg and dats for d kitten. For d dog. 20 kg – 3kg=17kg. Wif dat, d 3rd weight is sorted out. For d fourth, just add both 3 7 17(kg) and u’ll get 27kg.
There are 3 animals in consideration. A rabbit, a dog and something in form of a kitten.On d first scale was d kitten like animal and arabbit and dey jointly weigh10kg.Figuring out d weight ofeachanimal is impossible at dis point so we’ll look at d next set of animals ”dog kitten” with a joint weight of 20kg. D addition of both weights is equivalent to 30kg ie 10kg 20kg = 30kg. With our attention fixed on d third weight(d dog and kitten) which equals 24. Hence, 30kg-24kg = 6kg(subtracting d third weight from d addition of d first two weights). Since we av only a don and kitten on d third scale, it sure means dey share 24kg between demselves. And d 6kg goes to d rabbit and since we av d rabbit on two scales we can give d rabbit 3kg(x2 = 6kg) since d rabbit weighs 3kg, on d first scale 10kg – 3kg =7kg and dats for d kitten. For d dog. 20 kg – 3kg=17kg. Wif dat, d 3rd weight is sorted out. For d fourth, just add both 3 7 17(kg) and u’ll get 27kg.
There are 3 animals in consideration. A rabbit, a dog and something in form of a kitten.On d first scale was d kitten like animal and arabbit and dey jointly weigh10kg.Figuring out d weight ofeachanimal is impossible at dis point so we’ll look at d next set of animals ”dog+kitten” with a joint weight of 20kg. D addition of both weights is equivalent to 30kg ie 10kg + 20kg = 30kg. With our attention fixed on d third weight(d dog and kitten) which equals 24. Hence, 30kg-24kg = 6kg(subtracting d third weight from d addition of d first two weights). Since we av only a don and kitten on d third scale, it sure means dey share 24kg between demselves. And d 6kg goes to d rabbit and since we av d rabbit on two scales we can give d rabbit 3kg(x2 = 6kg) since d rabbit weighs 3kg, on d first scale 10kg – 3kg =7kg and dats for d kitten. For d dog. 20 kg – 3kg=17kg. Wif dat, d 3rd weight is sorted out. For d fourth, just add both 3 + 7 + 17(kg) and u’ll get 27kg.
27 or 28kg
29
The answer is 29
the correct answer is 27
Right again!
Final Answer 27KG. Kindly see my working as shown below:
Let R represent the Rabbit and S represent the Sheep and D represent the Dog
R= Rabbit, S=Sheep and D=Dog
From the Scale:
Rabbit + Sheep Only =10 kg
R + S = 10——– Equation (1)
Rabbit + Dog= 20 kg
R + D = 20 ——– Equation (2)
And
Dog + Sheep = 24 Kg
D + S = 24 ——– Equation (3)
From Equation (1), make R the subject of Formula, R being the Common Entity;
R + S = 10
R = (10 – S)
Substituting for R in Equation (2), we have
R + D = 20, so,
(10-S) + D = 20
Which becomes
D – S = 20-10
D – S = 10
D = (10 + S) ——– Equation (4)
Now Substituting D from Equtn 4 into Equatn 3
We have ,
D + s = 24 ——– Equation 3
(10 + S) +S =24
2S =24-10
S=14/2
S=7
From the Making of R the initial subject of formula
R = (10 – S)
R = ( 10 – 7)
R = 3
Now that we know the Weight of the Rabbit and that of the Sheep, by usinf equation 4 we have,
D = (10 + S)
D = (10 + 7)
D = 17
By Adding all the (R + S + D ) together we have the Weight of all the animals
Weight of all Animals = R + S + D = (3 + 7 + 17) = 27 Kg
Final Answer: 27 KG
Fantastic! It’s really obvious that you love Mathematics, and understand its concepts well. Do keep it up!
My Initial Post is Solving For Theory in WAEC/GCE , But in a UTM Exam , You need to be smart and use this method
Rabbit + Sheep = 10
Rabbit + Dog = 20
so , 2 Rabits + (1 sheep + 1 Dog) = 30 —-1
and Also
1 Sheep + 1 Dog = 24 —-2
2 R + (24)= 30
R = (30 – 24)/2 = 6/2
R= 3 WEIGHT OF I RABBIT
SO IF 1 SHEEP + I DOG = 24 KG
24 KG + 3 = 27KG , WEIGH OF ALL THE ANIMALS
FINAL ANSWER 27KG